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Mathematics 21 Online
OpenStudy (anonymous):

(x^4)^2

Parth (parthkohli):

\( \color{Black}{\Rightarrow (x \cdot x \cdot x \cdot x)(x \cdot x \cdot x \cdot x) }\)

Parth (parthkohli):

So if you are multiplying x by itself 8 times, then the expression you get is \(x^8\)

OpenStudy (anonymous):

(x^3y^5)^3 would it be x^9 y^15?

Parth (parthkohli):

Yea

OpenStudy (anonymous):

what would this be, would the fourteen by multiplied too? (14x^3y^2z)^4

Parth (parthkohli):

\( \color{Black}{\Rightarrow (14 \cdot x^3 \cdot y^2 \cdot z)^4 }\) \( \color{Black}{\Rightarrow 14^4 \cdot x^{12} \cdot y^8 \cdot z^4 }\)

OpenStudy (anonymous):

\[(a^x)^y = a^{x \times y}\]

OpenStudy (anonymous):

so is that the answer?

OpenStudy (anonymous):

What will be the answer you tell...

OpenStudy (turingtest):

@jalinnn it is considered rude on open study to not engage those trying to help you and simply request an answer. It is also not the point of this site. Please work with what ParthKohli and waterineyes are trying to tell you, and you will understand the problem.\Thanks

OpenStudy (anonymous):

that is what i asked if that was the answer because that is what i got. but that you very much for trying to tell me what this site is for. I just simply asked if that was the answer. that is not why i am on here

OpenStudy (anonymous):

That?? tell me the answer you got?

OpenStudy (anonymous):

38416x^12y^8z^4

OpenStudy (anonymous):

@waterineyes correct?

OpenStudy (anonymous):

Yes you are right @jalinnn

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