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Mathematics 18 Online
OpenStudy (anonymous):

Factor completely p4 – 2p2 + 1

OpenStudy (cwrw238):

(p^2-1)^2 [(p + 1)(p - 1)]^2

OpenStudy (cwrw238):

or you could write it as (p-1)^2(p + 1)^2

OpenStudy (anonymous):

thanks

OpenStudy (cwrw238):

yw

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