Question

Factor 3x5y3 – 27ax3y5 using the distributive property.

Answer 1

3x^5y^3-27ax^3y^5

Answer 2

@Loujoelou ....

Answer 3

I'm not really good at factoring stuff like this so yeah can't really tell if the answer I got is right in this instance :(

Answer 4

Just give me your answer.

Answer 5

I would think that the only thing you can factor is the 3 & 27 so
3(x^6y^3-9ax^3y^5) is what I think it would be.

Answer 6

A:xy3(x2 – 9ay2) C:3x3y3(x2 – 9ay2)
B:3x3y3(x2 + 9ay2) D:3xy3(x2 – 9ay2)

Answer 7

It would have to be answer C. That's the only thing that would then go back to your original number.

Answer 8

Thanks!

Answer 9

No prob. :)