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solve 0.002(7-k)+0.04(k-2)=1
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Hint: 0.002 = \(\frac{1}{500}\) 0.04 = \(\frac{1}{25}\)
Hint 2: \[\frac{19}{500}k-\frac{33}{500}=1\] Any more hints and I'd have to give away the answer ;-)
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