Question

The sum of the squares of 3 consecutive positive integers is 116. What are the numbers?

Which of the following equations is used in the process of solving this problem?
3n2 + 5 = 116
3n2 + 3n + 3 = 116
3n2 + 6n + 5 = 116

Answer 1

Consecutive integers would be represented by x, x+1, x+2
Squaring and summing them would make x^2+(x+1)^2+(x+2)^2=116
Now foil out the binomials and combine like terms.

Answer 2

thanks :)