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fencing off a rectangular playground. two length and 4 widths, 820 ft of fencing to be used. a. express the relationship between l, w, and total length. 2L+4W=820 b. Solve for L 2L+4W=820 2L=820-4W L=410-2W d. Make a quadratic using W- A=LW=(410-2W)(W)=-2W^2+410W c. Use this result to find the width W that maximizes the area A. Can't figure out this step... following question is use the result for D to find the maximum area and length.
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I think you should take derivative of A with respect to W..
what the heck does that mean haha
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