Question

*HELP been trying for hours!
Verify that quadrilateral BCDE is a rhombus with vertices B(-5, 1), C(0, -4), D(5, 1) and E (0, 6) by showing that all four sides are equal.
A. BD = CE = square root 50
B. BD = CE = 50
C. BC = CD = DE = EB = 50
D. BC = CD = DE = EB = square root 50
Help Please!

Answer 1

We have | BD | = \[\sqrt{(-5-0)^{2}+(1-(-4))^{2}} = \sqrt{25+25}= \sqrt{50}\]
Similar to | CE | = | DE | = | EB | .= \[\sqrt{50}\]
=> D is correct .

Answer 2

thank you so much!

Answer 3

yw :)