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Triangle ABC has the length of side AB as 10 centimeters. E is a point on AB and D is a point on BC. Points E and D are joined using a straight line. The measure of segment BD is 5 centimeters. The measure of angle BAC is equal to the measure of angle If the area of triangle ABC is 240 cm2, the area of triangle BDE is _____ cm2.
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This is a similar triangles problem, so you'll want proportions. So first off, can you show that triangle ABC is similar to triangle BDE?
5 seems to be seem similar to 10
BD seems to corresponds with AB
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Correct. Since area is proportional to the square of the side lengths, that means the area of the smaller triangle would be...
ahh
I think I have this one
the area is 60
Right on.
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