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Find S8 for the geometric series 3 + -6 + 12 + -24 +…
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A. -255 B. 768 C. -96 D. 192
\( \color{Black}{\Rightarrow \Large S_n = a{1 - r^n \over 1 - r} }\) a is the first term. r is the ratio. n is the number of terms.
\( \color{Black}{\Rightarrow \Large S_8 = 3{1 - (-2)^8 \over1 - (-2)} }\)
Note that 3 and that fraction are getting multiplied.
what is the answer though haha
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\( \color{Black}{\Rightarrow \Large 3 \times {1 + 2^8 \over 3}}\)
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