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Mathematics 18 Online
OpenStudy (anonymous):

What is the equation of the following graph

OpenStudy (anonymous):

OpenStudy (anonymous):

\[(x+1)^{2}+4y ^{2}=4\]

OpenStudy (anonymous):

@AIW hey i chose something different and your answer isnt a choice..

OpenStudy (anonymous):

@AIW is there another way to write it ?

OpenStudy (anonymous):

yes \[(x+1)^{2}\div2^{2}+y ^{2}\div1=1\]

OpenStudy (anonymous):

this?

OpenStudy (anonymous):

@AIW

OpenStudy (anonymous):

this is wrong because i you take y=o then \[(x+1)^{2}=1 => (x+1)=\pm1 =>x =0,-2\] which is not the case

OpenStudy (anonymous):

@AW which one? so confused

OpenStudy (anonymous):

@AIW

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