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Mathematics 9 Online
OpenStudy (anonymous):

sqrt(3+2*sqrt(2))

OpenStudy (anonymous):

\[\sqrt{3+2 \sqrt{2}}=\sqrt{1+2+2 \sqrt{2}}=\sqrt{1+(\sqrt{2})^2+2 \sqrt{2}}\]

OpenStudy (anonymous):

just notice \[1+2\sqrt{2}+(\sqrt{2})^2 \] is a complete square

OpenStudy (anonymous):

then what will u get?

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