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I'm confused. Solve for x: log(3)(x)=3
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\[\log_{3}x=3 \]
the base is 3
x = log(base b) of y is equivalent to y = b^x
\[Log_a(x) = b\] \[a^b = x\]
so 9 =x?
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Yes you are right..
x=1
not 3*3; 3^3
Thanks everyone!!!:)
oh so 729
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No the answer is wrong... Sorry..
3^3 = 3*3*3
\[x = 3^3 = 3 \times 3 \times 3 = ???\]
what the heck, lol I meant 27 idk why I put 729
:)
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Yes..
thank you!
the answer is x=1
uhhhhhhhh, how in the world did you manage to get that answer?
you said Solve for x log(3)(x)=3 3 x X = 3 BECAUSE X=1 SO 3X1=3 SO YOUR ANSWER IS = 3. SO TELL ME HOW YOU GET THE ANSWER =3 WHAT IS YOUR X
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YES THE CORRECT ANSWER IS X= 1
Why are you yelling?
your best bet is just to walk away and let them live in their own delusions ..... imo
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