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Mathematics 19 Online
OpenStudy (anonymous):

Choose the equation that could be used to find three consecutive integers whose sum is 75. n + (n + 1) + (n + 2) = 75 n + (n + 2) + (n + 4) = 75 n + (n + 1) + (n + 3) = 75 n + (n − 1) + (n − 3) = 75

OpenStudy (campbell_st):

its the 1st choice let the 1st integer be n, then the 2nd is n+1 and the 3rd n + 2 so n + n+1 + n +2 = 75

OpenStudy (anonymous):

thanks

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