Question

Let (x y^2) - (x^3 y)=6 and m = ((3x^2 y)-(y^2)) / ((2xy)-(x^3)). Find all points (x,y) on the curve where the slope is of the tangent line is horizontal, then vertical?

Answer 1

\[xy ^{2}-x ^{3}y=6 \] and \[m=(3x ^{2}y-y _{2})/(2xy-x ^{3})\]