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OpenStudy (anonymous):
A jar contains 6 yellow and 8 blue gumballs. Two gumballs will be drawn at random without being replaced. If the first gumball drawn is blue, what is the probability that the second gumball will also be blue? Leave answer as fraction.
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OpenStudy (anonymous):
well 7/13
OpenStudy (anonymous):
yeah I think so too
OpenStudy (anonymous):
reasoning is that you remove one blue gum then you have 7 blue left and 6 yellow hence 7/(7+6)=7/13
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