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Use the figure to find the measures. Area of circle = __ Area of sector O-AXB = __ Area of segment AXB = __ - __ Circumference = __
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@Calcmathlete
\[A_{\text{circle}}=\pi r^2\]
the area of the whole circle would b 36. but wat is the rest?
the are of the whole circle would be \[36 \pi\].
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rite. but wat r the other questions their askin for??
the sector is a quater of the circle
would i multiply 36 by 1/4??
the segment is the sector minus the triangle
\[C=2\pi r\]
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yeah multiply 36pi by 1/4 to find the area of the sector
ok thanx so much!! ;)
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