Question

Suppose the population of a town is 8,600 and is growing 3% each year. Predict the population after 3 years.
A. about 77,400 people

B. about 9,397 people

C. about 26574 people

D. about 232,200 people

Answer 1

are you allowed to use differential equations? i can solve this using that method...

Answer 2

I think so

Answer 3

B. about 9,397 people

Answer 4

ok what about this one..

Answer 5

Suppose that the population of deer in a state is 1,500 and is growing 2% each year. Predict the population after 4 years.
A. about 12,000 deer

B. about 1,624 deer

C. about 3,110 deer

D. about 24,000 deer

Answer 6

Firstly calculate 2 % of 1500..

Answer 7

@El-naggar are you sure about your answer? maybe you should provide a solution to prove your answer.

Answer 8

2% of 1500 is:
\[\frac{1500 \times 2}{100} = 30\]

After 4 years increase will be: 30 + 30 30 + 30 = 30*4 = 120

Just add 120 to the given population of deer and get the answer...

Answer 9

@lgbasallote it's easy 3% per year after 3 yrs the population increases with 9% and 9% of 8600 is 774 so after 3 yrs the population is 8600+774=9374