Question

What is the vertex of the graph of y =-2x^2+x+3?
a: 1/4, 25/8
b: -1/4, 27/8
c: 1/4, 27/8
d: -1/4, 25/8

Answer 1

You have to put it in vertex form

Answer 2

y=a(x-h)^2+k

Answer 3

is it a?

Answer 4

\[y=-2(x^2+1/2x)+3\]\[y=-2(x^2+1/2x+1/16)+3+1/8\]\[y=-2(x+1/4)^2+25/8\]
The vertex is (h,k)

Answer 5

So, if the equation, \[y=-2(x+1/4x)^2+25/8\] is in the form:\[y=a(x-h)^2+k\] Then what's the vertex?

Answer 6

i guessed a

Answer 7

The vertex is coordinate (h,k) in the equation I put in vertex-form... :)

Answer 8

The vertex is (-1/4, 25/8) keana :)