Question

N is a natural no formed by writing ,in the ascending order,the first 1002 whole numbers one after another.Find the remainder when N is divided by 9

Answer 1

Is the remainder 2??

Answer 2

Remainder of (N/9) = Rem(Sum of the digits of N/9) ... U CAN CHECK IT.

Now N=12345......999 1000 10001
UPTO 9999 no rema will be 0
for 1000 rem= sum of digit=1
for 1001 remainder= 2

therefoe ans= 1+2 =3

Answer 3

He gr8... thanks a lot vicky.

Answer 4

We can calculate the sum of digits from 0 to 1001.

\( \color{Black}{\Rightarrow \Large {1002 \over 2}({0 + 1001 )}}\)

Arithmetic sequence ^

Answer 5

\( \color{Black}{\Rightarrow 501(1001) = ......1 }\)

Answer 6

Hey lil correction: my ans is for digits upto 1001

for ur ques ... 1002 rem (when div by 9)= 3

net ans= 1+2+3=6

Answer 7

501501 ===> 5 + 1 + 1 + 5 = 1 + 2 = 3
3 is not divisible by 9, but 9 - 3 = 6

Answer 8

@Aprajita111 Did you understand?

Answer 9

Yes

Answer 10

Great!