Question

integral of = t^2 square root of t^3+1 dt .?

Answer 1

\[\large \int\limits\frac{t^{2}}{\sqrt{t^{3}+1}} dx\]?

Answer 2

\[\huge \int t^2 \sqrt{t^3+1}dt\]
let u = t^3 + 1
du = 3t^2dt

reqrite...
\[\LARGE \frac13 \int \sqrt u du\]
got it?

Answer 3

lol woops im blind

Answer 4

nope the t^2 is not over the the square root of t^3+1. :)

Answer 5

do you get my solution the @Beatles ?

Answer 6

yup but what is the answer? :)

Answer 7

please subtitue the value. :)

Answer 8

what do you mean?

Answer 9

well tell us what you got for the answer (:

Answer 10

Never mind. The answer is 1/3 (t^3+1)^3/2 :) is it correct?

Answer 11

i dont think so..

Answer 12

opps. I'm wrong. :)
this 2/9 (t^3+1)^3/2

Answer 13

+C haha

Answer 14

and yeah that's right

Answer 15

haha yah. :)