let f (x) x2 1 and g x 3x – 1. How would you Find f(g(x))

Question

campbell_st · Answer

f(g(x)) = f(3x -1) 

f(3x -1) = (3x -1)^2 + 1

just expand and simplify

anonymous · Answer

Expand?

anonymous · Answer

Yes now expand..

campbell_st · Answer

multiply to remove the bracket... perhaps distribute is you term

anonymous · Answer

Ummm..... Ill try... I am not sure about it though

campbell_st · Answer

can you expand a perfect square..?

anonymous · Answer

$$(a-b)^2 = a^2 + b^2 - 2ab$$

anonymous · Answer

I have never heard of that before.. to expand it ...

campbell_st · Answer

ummm thats interesting given the question you are attempting to answer...

campbell_st · Answer

are the 2 functions 

$$f(x) = x^2 + 1$$

and 

$$g(x) = 3x - 1$$

anonymous · Answer

.... Maybe my teacher used a diffrent word? I am not sure.... lol This is why I am lost

campbell_st · Answer

have you done any work on quadratics...?

anonymous · Answer

What am I doing to that? and no..... I am taking a quiz and this pops up...and i was dumbfounded

anonymous · Answer

thats not the right word. clueless is

campbell_st · Answer

lol... well just use the answer

f(g(x)) = (3x -1)^2 + 1

its just asking you to replace x with 3x - 1

anonymous · Answer

HAHA thaks so much. (: