Question

a^2+8a+15/a^2+7a+12 * 3a+12/a^2-25

someone please help

Answer 1

is it like this :

\[\huge{\frac{a^2+8a+15}{a^2+7a+12}*\frac{3a+12}{a^2-25}}\]

Answer 2

yes

Answer 3

ok then :

\[\huge{\frac{a^2+8a+15}{a^2+7a+12}}\]
i am simplifying this term first :
\[\huge{\frac{a^2+5a+3a+15}{a^2+4a+3a+12}}\]
\[\huge{\frac{(a+5)(a+3)}{(a+3)(a+4)}}\]

Answer 4

similarly simplify second term . what do you get?

Answer 5

8a^2/7a^2 ?

Answer 6

wait let me check

Answer 7

okay thank you

Answer 8

I actually have three choices. they are
-3/a+4
3(a+5)/a^2-25
3/a-5

@mathslover

Answer 9

3/a-5 is correct

Answer 10

alright thank you so much