Question

4.Write the equation of the line which passes through (2, –3) and is perpendicular to y = 4x + 7 in standard form.

Answer 1

perpendicular slopes are negative reciprocal of each other ( -1 divide by the slope)

find the new slope and put it in y = mx + b then substitute (2,-3) ~

Answer 2

it is perpendicular to y=4x+7.its slope will be -1/4
it also passes through (2,3)
so equation is
y-3=-1/4(x-2)

Answer 3

For the next step, you substitute x with 2 and y with 3.

Answer 4

y = mx + b
-3 = (-1/4)(2) + b
-3 = (-1/2) + b
-5/2 = b
one equation of the line is y = (-1/4)x - 5/2. The standard equation of a line is of the form Ax + By = C. We'll need to do some rearranging:
y = (-1/4)x - 5/2
y + (1/4)x = -5/2
4y + x = -10