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Mathematics 19 Online
OpenStudy (anonymous):

What are the solution intervals for |2x + 7| – 3 > 2? x < 6 and x > –1 x > –6 and x < 1 x < –6 or x > –1 x > 6 or x < –1

OpenStudy (anonymous):

First option

OpenStudy (jackellyn):

|2x+7| -3 +3 > 2+3 |2x+7| > 5 2x+7 > 5 2x+7 > -5 2x > 5-7 2x > -5 +7 x > (5-7)/2 x > (-5+7)/2 x > ? x > ?

OpenStudy (anonymous):

|2x + 7| – 3 > 2; |2x + 7| > 5; -5 > 2x + 7 > 5; -12 > 2x > -2; -6 > x > -1 ; so x < -6 and x > -1 third option

OpenStudy (anonymous):

yeah @knock is correct. my bad.

OpenStudy (anonymous):

(:

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