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OpenStudy (anonymous):

What is the measure of angle HLF?

OpenStudy (anonymous):

OpenStudy (anonymous):

@apoorvk I know you use tangent, right? but how do you set up the answer?

OpenStudy (apoorvk):

well, if you remember trigonometry, \(\Large\tan\theta = \frac{perpendicular}{base}\) So here, \(\Large\tan C = \frac{AB}{BC}\) Can you use this?

OpenStudy (anonymous):

OpenStudy (anonymous):

is that right?

OpenStudy (apoorvk):

Umm, this time you actually blooped. :| Now worries, here's how it's done \(\frac{AB}{BC} = \tan 45^o\) Now,we cross multiply, and send that BC over to RHS: \(or,~AB = BC \times \tan45^o\) Now, BC=12. and tan45=1 so find AB!

OpenStudy (apoorvk):

Www-wait a sec - what's 'angle HLF'????

OpenStudy (anonymous):

45 degres i attached the pic^^

OpenStudy (anonymous):

am i right ? @apoorvk

OpenStudy (apoorvk):

But the figure you attached is named as ABC!

OpenStudy (apoorvk):

anyways, if angle BAC has been asked, then it is ofcourse 45 degrees by sing the angles sum property of a triangle.

OpenStudy (apoorvk):

(and also, could you please post these maths questions in the Mathematics forum? Thanks :) )

OpenStudy (anonymous):

OMG! sorry this is the question -.-What is the height, in feet, of the portion AB of the lamp post?

OpenStudy (apoorvk):

yeah, so I showed you how to find AB above, could you go through that comment again please? :)

OpenStudy (anonymous):

so im right :))))

OpenStudy (anonymous):

OpenStudy (anonymous):

@apoorvk

OpenStudy (apoorvk):

No!!! it's 12*tan45, not 12/tan45 (although numerically they are both same since tan45=1, but you'll get into trouble if the angle is something other than 45 degrees)

OpenStudy (anonymous):

gotha ya :)

OpenStudy (apoorvk):

Yo!

OpenStudy (apoorvk):

and please post in 'maths' section thanks :)

OpenStudy (anonymous):

how do i do tht

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