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16 < 2x + 4 < 4 Solve the inequality above
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So you do to one of them, you do to all three.
subtract 4 from all three \( \color{Black}{\Rightarrow 12 < 2x < 0}\) divide all three by 2. \( \color{Black}{\Rightarrow 6 < x < 0 }\)
Describe the graph of the solution
no solution???? if x>6, x can't be less than 0
did you write the original problem correct? perhaps it is missing a symbol or sign? I see what you are saying 6<0 is a false statement 0 is not bigger than 6
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