for f(x)=3x+1 and g(x)=x^2-6, find(f/g)(x)

A. 3x+1/x^2-6

B. 3x+1/x^2-6, x does not = +/- sqrt6

C. x^2-6/3x+1

D. x^2-6/3x+1, x does not = -1/3

Question

for f(x)=3x+1 and g(x)=x^2-6, find(f/g)(x)
 
A. 3x+1/x^2-6
 
B. 3x+1/x^2-6, x does not = +/- sqrt6
 
C. x^2-6/3x+1
 
D. x^2-6/3x+1, x does not = -1/3

lgbasallote · Answer

do you have a bet on which it is?

anonymous · Answer

A

anonymous · Answer

or B

lgbasallote · Answer

close..it's B because B states the domain...x cannot be +/- sqrt 6 because if it is...the thingy will become undefined since it will become 3x + 1/0

got it?

lgbasallote · Answer

usually if it's specific..you have more reason to choose it lol

anonymous · Answer

yeah lol the thingy :) got it though thank you for all your help!

lgbasallote · Answer

$$\huge \color{maroon}{\mathtt{\text{<tips hat>}}}$$