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Can someone help me please? Factor the following expression completely: 2x^2+2x-144
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Make the factors of -288 that will make the sum = 2..
start by factoring out the common factor of 2 and write \[2(x^2-x+72)\]
well that was wrong should be \[2(x^2+x-72)\]
then think if you can find two numbers whose difference is one (i.e. they are one apart) and whose product is 72 guess and check for this one. you will see that 8 and 9 work because they are one apart and multiply together to get 72
so you can write \[2(x-8)(x+9)\]
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