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If cos= 2 to the square root of 10 over 7 calculate the value of sin a. 3/7 b. square root of 29/7 c. square root of 69/7 d. square root of 89/7
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can you rewrite the question? as of now, it don't make no sense....
\[\cos= 2\sqrt{10}/7\]
draw the triangle |dw:1341095854598:dw| find the missing side using pythagoras then sin = 3/7
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