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how can i factor 125-y cube
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(125-y)^3 = (125-y)(125-y)(125-y). Its already factored to its simplest form Unless they want you to distribute the cubic aspect.
just like this 125-y^3
it's like 5^3 - y^3 use a^3 - b^3
a3 − b3 = (a−b)(a2 + ab + b2)
an - bn = (a-b)(an-1 + an-2b + an-3b2 + +bn-1)
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thanks!! it really works
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