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OpenStudy (anonymous):
prime factors of x3-1.
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OpenStudy (anonymous):
(x)^3-(1)^3 using a^3-b^3=(a-b)(a2+b2+ab) we get (x-1)(x2+1+x)
OpenStudy (anonymous):
how about 125-y3 ? :]]
OpenStudy (anonymous):
putting a=5 and b=y in the same identity
OpenStudy (anonymous):
ty :]
OpenStudy (anonymous):
ur welcome
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