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Mathematics 19 Online
OpenStudy (anonymous):

prime factors of x3-1.

OpenStudy (anonymous):

(x)^3-(1)^3 using a^3-b^3=(a-b)(a2+b2+ab) we get (x-1)(x2+1+x)

OpenStudy (anonymous):

how about 125-y3 ? :]]

OpenStudy (anonymous):

putting a=5 and b=y in the same identity

OpenStudy (anonymous):

ty :]

OpenStudy (anonymous):

ur welcome

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