This is a word problem involving simple interest: Pat invested $3000, part went into an acct that paid 10% simple annual interest, and another part went into an acct that paid 8% simple annual interest. If the total interest at the end of the year was $256, how much with the investment in each acct at the beginning of the year?

Question

slaaibak · Answer

x(.08) + (3000 - x)(1.1) = 256

Solve that.

anonymous · Answer

Does the 1.1 come from the 10% part?

slaaibak · Answer

Sorry I made a typo.

It should be 

x(.08) + (3000 - x)(0.1) = 256

where the .08 is from the 8% and the 0.1 is from the 10%

anonymous · Answer

I think I'm messing this up somehow... I ended up with X= -11,300. LOL
I know that's not right

anonymous · Answer

@Limitless , can you help me?