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Solve |2y - 2| = y. Answer {2/3, 2} {2, 3} {2, 5} {1/3, 2}
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\(\Rightarrow 2y - 2 = \pm y \) This is a good start
Or you can think of it as |2y - 2| = y breaking up into 2y - 2 = y or 2y - 2 = -y
would it be (1/3, 2)
no, part of that is correct though
ie, one of those numbers is correct
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the 2 is correct.
Yes, 2 is correct.
Now start with the second equation.
Okay so now im getting (2/3, 2)
Yep!
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