Question

the perimeter of a rectangle is 38 ft the length is 3 ft longer than the width.
write a system of linear equations and solve the resulting system let x be the length and y b the width
2x +2y = ?
x= y + ?

Answer 1

2x + 2y = 38

then x = 19 - y

Answer 2

campbell_st can you expand on that answer please

Answer 3

well you know that

x = 3 + y

that is the rectangle is 3 units longer than the width

then the equations are

x = 3 + y (1)
x = 19 - y (2)

equate the equations

3 + y = 19 - y

add y to both sides

3 + 2y = 19

subtract 3 from both sides

2y = 16

or y = 8

then the width is 8 units

so length = 11 units found by substituting into equation 2 above