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Mathematics 13 Online
OpenStudy (anonymous):

Verify the identity: Use the fundamental , sum-difference , & double-angle identities in the steps. tan8k - tan8k tan²4k = 2tan4k

OpenStudy (anonymous):

Firstly take out tan8k as common.. Tell me what you are left with??

OpenStudy (anonymous):

tan 8k ( 1- tan²4k)

OpenStudy (anonymous):

Yes.. Now use this formula for tan8k.. \[\tan2A = \frac{2tanA}{1 - \tan^2A}\]

OpenStudy (anonymous):

8k = 2A So, A = 4k.. Use the above formula where A = 4k..

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