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Verify the identity: Use the fundamental , sum-difference , & double-angle identities in the steps. tan8k - tan8k tan²4k = 2tan4k
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Firstly take out tan8k as common.. Tell me what you are left with??
tan 8k ( 1- tan²4k)
Yes.. Now use this formula for tan8k.. \[\tan2A = \frac{2tanA}{1 - \tan^2A}\]
8k = 2A So, A = 4k.. Use the above formula where A = 4k..
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