Question

\[\int{cos^2 x}\]=?
and
\[\int{sin^3 x}\]=?
Explain the steps you have done.

Answer 1

\[\int\limits\frac{1+\cos2x}{2} dx\]

Answer 2

Since, \[\cos^2x = \frac{1+\cos2x}{2} \]

Answer 3

\[\sin^2x = \frac{1-\cos2x}{2} \]

Answer 4

it's \[\Huge\sin^3 x\]

Answer 5

\[\int\limits \sin^{3} xdx => \int\limits \sin^{2} xsinxdx => \int\limits(1-\cos^{2} x)(sinxdx\]

Answer 6

Thank you I get it

Answer 7

np