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How many different 5 card hands can be drawn from a standard deck of 52 cards?
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52C5
i believe you use combination \[\huge \frac{n!}{r!(n-r)!}\]
You can simplify that thing: \(\Rightarrow \Large {52! \over (52 - 5)! 5!} \)
where n = 52 and r = 5
got it @shivraj
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yes
great! glad to hear :D
\[^nC_r = \frac{n!}{(n-r)! \times r!}\]
\(\Rightarrow \Large {52 \times 51\times 50 \times 49 \times 48 \over 5 \times 4 \times 3 \times 2 \times 1 }\)
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