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OpenStudy (anonymous):
5^(x-2)25^(4x)=(1)/(√(125^(2x+3))) Find x
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OpenStudy (anonymous):
x=0.069
OpenStudy (anonymous):
how to do?
OpenStudy (anonymous):
\[(x-2)*25^{4x}\log5_{5} = (-1/2) * (2*x+3)*\log125_{5}; (x-2)*25^{4x}=-3*x-4.5\]
OpenStudy (anonymous):
erm i dont know how to do logarithm yet.
OpenStudy (anonymous):
without him nothing
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