Question

he sum of three numbers is 26. The second number is twice the first and the third number is 6 more than the second. Find the numbers.

Answer 1

Let the first no. be x.
then 2nd no. = 2x
and 3rd no. = 2x+6

Now, x+(2x)+(2x+6)=26
5x=26-6
5x=20
x=4

first no. = 4
2nd no. = 2x = 8
3rd no. = 2x+6 = 14

Answer 2

Let the second number be: s
Let the first number be : f
Le the third number be : t



So, s = 2f

t = 6 + s

So,

f + s + t = 26

s/2 + s + 6 + s = 26

5s + 12 = 52

Find s from here..