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can anyone help me to the answer for this... (will post equation in a sec...)
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\[\sqrt{\sqrt{x-2}+x}=2\]
Square both sides
root(x-2) + x =4 root(x-2) = 4-x square again
x-2 = 16 - 8x + x^2 9x = 18 + x^2 x^2 - 9x + 18 = 0
(x-6)(x-3)=0 x=6 or x=3
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@niravshah08 how on earth did you get the first line x-2 = 16 - 8x + x^2 ???
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