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If you were to use the substitution method to solve the following system, choose the new system of equations that would result if x was isolated in the third equation. 2x – 3y + z = –4 2x – 2y + z = –1 x – 2y + 3z = –6 A. 5x + 7y = 6 y – 4 = –1 B. –y – 1 = –4 –5x + 4y = –3 C. y – 5z = 8 2y – 5z = 11 D.–7y + 7z = 8 –6y + 7z = 11
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