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(4w2 – 7w – 6) – (8w2 + 2w – 3) A. –4w2 – 9w – 3 B. 12w2 + 9w + 3 C. –4w2 – 5w – 9 D. 12w2 – 5w – 9
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is this how I start it out? (4w^2-8w^2)-(7w-2w)-(6-3)
\[(4w^{2} - 7w - 6) - (8w^{2} + 2w - 3) = 4w^{2} - 7w - 6 - 8w^{2} - 2w + 3\]Are you with me so far?
no
-4w^2-5w-3
Okay. Do you realize when it says \(-(8w^{2} + 2w - 3)\), it means \(-1(8w^{2} + 2w - 3)\)?
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yes
is this right? -4w^2-5w-3
For the final answer, not quite. It would be \(-4w^{2} - 9w - 3\)
how did you get 9w
A is right sure
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-7w - 2w = -9w
That's how I got the -9w.
change the minus to a plus and change the sign
Yeah. -7w + -2w = -9w.
ok got it. might need help soon. thank you
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np :)
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