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Simplify : a^4(a^-1)(a^3) a. a^7 b. a^12 c. a^6
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Use these two rules: \[\huge x^{a} \times x^{b} = x^{a + b}\]\[\huge x^{-a} = \frac{1}{x^{a}}\]
Would it be C?
Yes :)
Thanks! @Calcmathlete
np :)
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