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find all of the real roots of x^3-7x+6=0
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Put x = 1 in the equation and check whether the result is coming 0 or not?? Do it..
yes
and if x=-3:)
so, (x-1) is the factor of this equation.. Now by long division divide x^3 - 7x + 6 with (x - 1) and find the quotient..
use synthetic divison for finding real roots
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