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find the diff. eq.: yx^2= 1 + cx
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differential equation?
yes.. opo.. :)
is this even a differential equation? o.O where's the differential here?
differentiate it once wrt x and eliminate c to get the required diff. equation yx^2= 1 + (2xy+x^2(dy/dx))x
eliminate the arbitrary constant c
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oh lol..i didnt know that method
ok.. its too damn hard..
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