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IVP problem.
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ln y = -lnx +lnx +c Conditions are y(2)=1
I got y=e^-lnx* e^lnx* e^c
I am not sure how to simplify further.
isnt it simply y = k ? (k = e^c)
What do you mean? I need to find the value for the constant.
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y(x) = c Given: y(2) = 1 from our solution: y(2) = c so, c = 1 the solution is y(x) = 1
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