What is the product of 4/t-3 * 2t-6/16^3
A. t-3/2t^2, t =/ 0,3
B. t-3/2t^3, t =/ 0,3
C. 1/2t^2, t =/ 0,3
D. 1/2t^3, t =/ 0,3

Question

What is the product of 4/t-3 * 2t-6/16^3
A. t-3/2t^2, t =/ 0,3
B. t-3/2t^3, t =/ 0,3
C. 1/2t^2, t =/ 0,3
D. 1/2t^3, t =/ 0,3

jhonyy9 · Answer

opinion ?

jhonyy9 · Answer

4       2(t-3)
--- * ------ =
t-3      16^3

can you continue ?

anonymous · Answer

Yes, I had already got C before, but was in fact wondering if it was correct?

jhonyy9 · Answer

and now do you know it ?

jhonyy9 · Answer

so than i think that you have missed anything from this exersice 

please you ,check it !!!

jhonyy9 · Answer

so because how i have wrote before and if you check it nely so than you can seeing that there you will can simplifie t-3 and with this t will be eliminated from this fraction

jhonyy9 · Answer

for being C. the right option so for this 16^3 need being 16t^2

anonymous · Answer

I have t+2/4t^3, is that right? I cancel out 2 and 4 to make 2 then cancel out t and t^3 to make t^2 so the answer is 1/2t^2?

jhonyy9 · Answer

can you rewrite here your exersice newly RIGHT here please ???