Question

What are the solutions of the system?

y=x^2+4x-5
y=2x-2



A. (–3, –8) and (1, 0)

B. (–3, –8) and (–1, –4)

C. (–3, 0) and (1, –8)

D. no solution

Answer 1

so one please help?

Answer 2

I think it is D but not sure.

Answer 3

y=x^2+4x-5 -(1)
y=2x-2 -(2)
(1)- (2):
0 = x^2 +4x -5 - (2x-2)
0 = x^2 +2x -3
(x+3)(x-1) =0
x= -3 or x =1
When x = -3.
y = (-3)^2 + 4(-3) -5 = -8
So, (-3, -8) is a pair of solutions
When x = 1
y = (1)^2 + 4(1) -5 = 0
So, (1, 0) is another pair of solutions.

Answer 4

so the answer would be A.

Answer 5

Yes... I hope you know where you got wrong...

Answer 6

i do thanks

Answer 7

Welcome :)