The three Math Idol judges have been eliminating contestants all day! The number of one-step equations and two-step equations who have been eliminated today is equal to 1120. If three times the number of one-step equations minus twice the number of two-step equations is equal to 1300, how many two-step equations auditioned today?

a. 1300

b.1120

c.708

d.412

Question

The three Math Idol judges have been eliminating contestants all day! The number of one-step equations and two-step equations who have been eliminated today is equal to 1120. If three times the number of one-step equations minus twice the number of two-step equations is equal to 1300, how many two-step equations auditioned today?

a. 1300

 b.1120

 c.708

 d.412

diyadiya · Answer

Let the number of 1 step equations be $x$ and 2 step equations be $y$

anonymous · Answer

ok:
# of one step equations -- X
# of two step equations -- Y
X + Y = 1150 (the total eliminated)
3X - 2Y = 1300 (second equation)


ok now find the value of Y in terms of X from the first equation EX. if 4X + 2Y = 600, the value of Y in terms of X is 2Y = 600 - 4X ----> Y = 300 - 2X 

Now substitue the new value of Y into the second equation and solve for X