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For the following system, if you isolated x in the first equation to use the Substitution Method, what expression would you substitute into the second equation? 3x + 15y = 33 4x − 3y = 6
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x = 33 - 15y / 3
Isolating x, 3x + 15y = 33 3x=33-15y \[x=\frac{33-15y}{3}\] \[x=11-5y\] substitute to second equation 4x − 3y = 6 4(11-5y) − 3y = 6 solve for y
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